如图甲所示,两根足够长的光滑平行金属导轨相距为 L =0.40m ,导轨平面与水平面成θ=30°角,上端和下

2025-05-11 02:10:49
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回答1:

解:(1) =mgsin30°+ ,B=1 T
(2) -mgsin30°- =ma ,a= m/s 2
(3)F-mgsin30°- =ma ,F = t+ N
(4)Q 1 =( 2 ×1.2=0.3I 2 ,Q r =0.2I 2 ,Q =2Q 1 +Q r =0.36 J