如图,AB=AC,AD=AE,点B、D、E、C在同一条直线上,求证:BD=CE

2025-05-10 21:37:09
推荐回答(2个)
回答1:

先证全等,,△ABD全等与△ACE,,

AB=AC AD=AE ∴∠B=∠C ∠ADE=∠AED

∠ADE=∠AED∴∠ADB=∠AEC
∵∠B=∠C
∠ADB=∠AEC
∴∠BAD=∠CAE

∠BAD=∠CAE
AB=AC
∠B=∠C

▲ABD

▲ACE
∴BD=CE

睿智为您解题,,希望您能满意,,

回答2:

因为AB=CA,所以角ABC=角CAB,又因为AD=AE.所以角ADE=角AED.所以角ADB=角AEC,
{角B=角C,角ADB=角CEA,AB=CA}所以三角形BAD全等三角形CAE,所以BD=CE