如图所示
（7） y = 1/(x^2-1) = 1/[(x-1)(x+1)] = (1/2)[1/(x-1)-1/(x+1)]
y' = (1/2)[-1/(x-1)^2 - (-1)/(x+1)^2]
y'' = (1/2)[(-1)(-2)/(x-1)^2 - (-1)(-2)/(x+1)^2]
y''' = (1/2)[(-1)^3 3!/(x-1)^3 - (-1)^3 3!/(x+1)^3]
.............................................
y^(n) = (-1)^n (1/2) n! [1/(x-1)^n - 1/(x+1)^n]
y^(5) = -60[1/(x-1)^5-1/(x+1)^5]
希望写的比较清楚，望采纳哦
内容全部来源于网络收集，如有侵权，请联系网站删除：QQ：24596024