如图,一座水坝的横截面是梯形ABCD,背水坡AB的坡度i(即tanα)为1:1,迎水坡CD的坡角为30°,坝顶宽为

2025-05-11 00:27:02
推荐回答(1个)
回答1:

解答:解:(1)过A和D分别作垂线交BC于点E,F,
由题意得AE=DF=7,又tanα=1
∴BE=AE=7,AB=7

2
=9.9米;

(2)由DF=7,∠C=30°可得CF=7
3
=12.1米,
BC=BE+EF+CF=7+6+12.1=25.1米;
答:AB的长为9.9m;坝底宽BC长为25.1m.