先化简,再求值:(1)(3x2y-xy2)-3(-2xy2+x2y),其中x=12,y=?13;(2)3x3-[x3+(6x2-7x)]-2(x

2025-05-11 02:31:45
推荐回答(1个)
回答1:

(1)原式=3x2y-xy2+6xy2-3x2y=5xy2
∵x=

1
2
,y=-
1
3

∴原式=
5
18

(2)原式=3x3-x3-6x2+7x-2x3+6x2+8x=15x,
∵x=-1,
∴原式=-15.