化简求值:先化简再求值:当x=?12,y=1时,求代数式5(3x2y-xy2)-(xy2+3x2y)的值

2025-05-08 02:48:18
推荐回答(1个)
回答1:

原式=15x2y-5xy2-xy2-3x2y
=12x2y-6xy2
当x=-

1
2
,y=1时,原式=3+3=6.