线性代数大神们,求解第五题,谢谢啦

2025-05-08 07:41:41
推荐回答(2个)
回答1:

回答2:

A=(1 2 3)'(1 1 1)
A^2005=(1 2 3)'(1 1 1)(1 2 3)'(1 1 1)...
=(1 2 3)'6*6*6*...*(1 1 1)
=6^2004(1 2 3)'(1 1 1)
=6^2004A
或者特征值通用算法.