初二数学化简计算题 跪求各位大神解答

2025-05-10 08:33:06
推荐回答(2个)
回答1:

 

 

回答2:

计算1=a^3/b^3
xy(x+y)/(x-y)^2*(x-y)/(xy+y^2)=x/(x-y)
(16-a^2)/(a^2+8a+16)÷(a-4)/(2a+8)=(4+a)(4-a)/(a+4)^2÷(a-4)/2(a+4)=-2
(a-1)/(a-2)÷(a^2-2a+1)/(2a-4)=(a-1)/(a-2)*2(a-2)/(a-1)^2=2/(a-1)