#include
//求10~200的回文数,每行输出5个,
//在主函数中输出,fun(int n)来实现
int fun(int n)
{
int reverse_of_num=0, tmp =n;
while(tmp)
{
reverse_of_num = reverse_of_num*10 + tmp%10;
tmp=tmp/10;
}
if(reverse_of_num == n)
return 1;
else
return 0;
}
int main ()
{
int i = 0,num = 0;
printf("10~200的回文数:\r\n");
for(i = 10 ;i<=200;i++)
{
if(fun(i))
{
printf("%d\t",i);
num ++;
if(num % 5 == 0)
printf("\n");
}
}
return 0;
}