设L为圆周x2+y2+2y=0,则∮ L(y4x+x5)ds=______

设L为圆周x2+y2+2y=0,则∮ L(y4x+x5)ds=______.
2025-05-10 10:09:19
推荐回答(1个)
回答1:

∵L为圆周x2+y2+2y=0,L的极坐标方程为:r=-2sinθ,π≤θ≤2π
则x=-2sinθcosθ,y=-2sin2θ,ds=

r2+r2
dθ=2dθ
L
(y4x+x5)ds
=
[(?2)4sin8θ?(?2sinθcosθ)?25sin5θcos5θ]2dθ

=?26
[sin9θ+sin5θ?(1?sin2θ)2]dsinθ

=?26
[t9?t5(1?t2)2]dt
  令t=sinθ
=0