高数第6题怎么做?

请看第六题,谢谢!
2025-05-09 05:48:49
推荐回答(1个)
回答1:

x=t - arctant,y=ln(1+t²),
则 dy/dx = (dy/dt) / (dx/dt)
=[2t/(1+t²)] / [1 - 1/(1+t²)]
=2 / t,
d²y/dx² = d(dy/dx) / dx
=(-2/t²) / [1 - 1/(1+t²)]
=-2(1+t²) / t^4