已知代数式M=x2+2y2+z2-2xy-8y+2z+17.1)若代数式M的值为零,求此时x,y,z的值

2025-05-14 22:07:44
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回答1:

解:(1)∵x^2+2y^2+z^2-2xy-8y+2z+17=0,
∴(x-y)^2+(y-4)^2+(z+1)^2=0,
∵(x-y)^2≥0,(y-4)^2≥0,(z+1)^2≥0,
∴(x-y)^2=0,(y-4)^2=0,(z+1)^2=0,
∴x-y=0,y-4=0,z+1=0,
∴x=y=4,z=-1,

(2)x=2,y=3,z=0.
把M代入,
x^2+2y^2+z^2-2xy-8y+2z+17+x^2≤7