通分[x-2(x-3)]/(x-3)=m/(x-2)(6-x)/(x-3)=m/(x-2)(6-x)(x-2)=m(x-3)6x-x²-12+2x²=mx-3mx²+(6-m)x+3m-12=0有一个正整数解，且x≠2和3∴△=（6-m）²-4（3m-12）=m²-12m+36-12m+48=m²-24m+84=0（m-12）²=60m=12±2根号15
