若x-3的绝对值与。X,加y-7的绝对值的值互为相反数,求代数式x y分之x-y的值等于多少?

2025-05-11 02:22:31
推荐回答(2个)
回答1:

| x-3 |=-| x+y-7|
x-3=0 x=3
x+y-7=0
y=7-3=4
(x-y)/(x+y)
=(3-4)/(3+4)
=-1/7
=-7分之1

回答2:

结果:-12分之1