①CH4(g)+4NO2(g)═4NO(g)+CO2(g)+2H2O(g)△H=-574kJ?mol-l
②CH4(g)+4NO(g)═2N2(g)+CO2(g)+2H2 O(g)△H=-1160kJ?mol-l
③H2O(g)═H2O(l)△H=-44.0kJ?mol-l
依据盖斯定律计算[①+②+③×4]×
得到CH4(g)与NO2(g)反应生成N2(g)、CO2(g)和H2O(l)的热化学方程式:CH4(g)+2NO2(g)=N2(g)+CO2(g)+2H2O(l)△H=-955 kJ?mol-1;1 2
故答案为:CH4(g)+2NO2(g)=N2(g)+CO2(g)+2H2O(l)△H=-955 kJ?mol-1.