将1molCnHmO2的有机物在氧气中完全燃烧后,生成的CO2和H2O(g)的体积相等,并消耗78.4LO2(标准状况).

2025-05-10 23:58:53
推荐回答(1个)
回答1:

n(O2)=

78.4L
22.4L/mol
=3.5mol,
CnHmO2+(n+
m
4
-1)O2
d点燃
nCO2+
m
2
H2O
1       n+
m
4
-1
1       3.5
则:
m=2n
n+
m
4
?1=3.5

解得n=3,
故选:B.