已知二元一次方程组{2x+y=7;x+2y=8,则x-y=____,x+y=___

2025-03-05 23:04:57
推荐回答(3个)
回答1:

x-y
=(2x+y)-(x+2y)
=7-8
=-1

x+y
=[(2x+y)+(x+2y)]÷3
=(7+8)÷3
=5

回答2:

解:2x+y=7 ①
x+2y=8 ②
由 ①+②得:2x+y+x+2y=15,3x+3y=15,3(x+y)=15,x+y=5
由 ①-②得:2x+y-x-2y=-1,x-y=-1
综上所述:x-y=-1,x+y=5
祝您做题愉快!

回答3:

x-y=-1,x+y=5