在底面为平行四边形的四棱锥p-abcd中,ab⊥ac,pa⊥平面abcd,点e是pd的中点。1求证ac⊥pb.2求证pb∥...

2025-05-11 20:03:14
推荐回答(3个)
回答1:

(1)∵pa⊥平面abcd,ac在平面abcd内、
∴pa⊥ac
∴ac⊥平面pab,∵pb属于平面pab
∴ac⊥pb

(2)连接bd交ac与o,连接eo
∵o、e分别为bd,pd的中点,∴在△pbd中、eo∥pb
∵eo属于平面aec
∴pb∥平面aec

回答2:

记AC与BD交点为O,设AO=x,BO=y,
则梯形面积为1/2(AO*BO+BO*CO+CO*DO+DO*AO)=1/2(xy+y(5-x)+(5-x)(4-y)+(4-y)x)
=1/2(xy+5y-xy+20-5y-4x+xy+4x-xy)=1/2*20=10

回答3:

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