∵a,b,c都是质数,且满足a+b+c+abc=99,∴a=2,b=2,c=19,满足题设,故原式=| 1 2 - 1 2 |+| 1 2 - 1 19 |+| 1 19 ? 1 2 |= 17 19 .故答案为 17 19 .