(1/2+√3/2)x+(1/3-√3/2)y-1/2+√3=0(3+3√3)x+(2-3√3)y-3+6√3=03x+3√3x+2y-3√3y-3+6√3=03x+2y-3+3(x-y)√3+6√3=0 3x+2y-3=03(x-y)-6=0x=7 y=-9
