ajax调用后台一个方法,并且给这个方法传递一个值

2025-05-11 11:34:39
推荐回答(1个)
回答1:

xmlhttp.open("GET","ReceivablesRecord/receivables!showCountySeat.action",true);

改为
xmlhttp.open("GET","ReceivablesRecord/receivables!showCountySeat.action?Location="+x,true);