x是什么值时,代数式(x-2)/3-(x-1)/4与(1-x)/6的值互为相反数(x-2)/3-(x-1)/4与(1-x)/6的值互为相反数则(x-2)/3-(x-1)/4+(1-x)/6=04(x-2)-3(x-1)+2(1-x)=04x-8-3x+3+2-2x=0-x=3x=-3
