大一高数,不定积分,求详解,谢谢!

2025-05-11 09:19:20
推荐回答(2个)
回答1:

回答2:

解:
令x=asint,则dx=acost dt
∫x²/√(a²-x²) dx
=∫a²sin²t/(acost)·acostdt
=a²∫sin²t dt
=a²∫(1-cos2t)/2 dt
=a²∫1/2dt-a²∫cos2tdt
=a²t/2-1/2·a²sin2t+C
=1/2·a²arcsin(x/a)-x·√(a²-x²)+C