我就破例再给你写一道。(1)证：∵AF=CE∴AF+EF=CE+EF即AE=CF∵AD=BCDE=BF∴△ADE≌△CBF(SSS)(2)成立。∵AF=CE∴AF-EF=CE-EF即AE=CF∵AD=BCDE=BF∴△ADE≌△CBF(SSS)(3)平行∵△ADE≌△CBF∴∠A=∠C∴AD∥CB
