已知等差数列{a n }的前n项和为S n ,若 OB = a 5 OA + a 6

2025-05-13 17:24:29
推荐回答(1个)
回答1:

OB
= a 5
OA
+ a 6
OC

O为坐标原点,且A,B,C三点共线,
∴a 5 +a 6 =1,
∵数列是一个等差数列,
∴a 1 +a 10 =1
∴S 10 =
10( a 1 + a 10 )
2
=5
故选B.