先化简,再求值:(1)4(3x2-xy2)-(xy2+3x2y),其中x=12,y=-1;(2)3x2y-[2xy--2(xy-32x2y)+xy]

2025-05-11 02:51:18
推荐回答(1个)
回答1:

(1)原式=12x2-4xy2-xy2-3x2y=12x2-5xy2-3x2y,
当x=

1
2
,y=-1时,3-2.5+0.75=1.25;
(2)原式=3x2y-2xy+2xy-3x2y-xy=-xy,
当x=3,y=-
1
3
时,原式=1.