3(4) lny = (1/2)ln|x+2| + 4ln|x-3| - 5ln|x+1|y'/y = (1/2)/(x+2) + 4/(x-3) - 5/(x+1)y' = y[(1/2)/(x+2) + 4/(x-3) - 5/(x+1)]= {√(x+2)(x-3)^4/(x+1)^5]}[(1/2)/(x+2) + 4/(x-3) - 5/(x+1)]
