详细过程在这里，希望有所帮助，望采纳
解，f(x-2)=logα[(3-x)/(x-1)] f(4-3x)=loga[(3x-3)/(5-3x)] 则(3-x)/(x-1)>0① (3x-3)/(5-3x)>0② (3x-3)/(5-3x)*(3-x)/(x-1)≥1③由①得1①，②，成立③成立。则x∈(1，5/3)
