先化简,再求值:(1)5xy2-2x2y+4xy2-3x2y,其中x=-1,y=1.(2)先化简,再求值:3x2-[x2-2(3x-x2)]

2025-05-11 00:03:54
推荐回答(1个)
回答1:

(1)原式=(5+4)xy2-(2+3)x2y
=9xy2-5x2y,
当x=-1,y=1时,原式=9×(-1)×12-5×(-1)2×1=-14;

(2)原式=3x2-[x2-6x+2x2]
=3x2-3x2+6x
=6x
当x=-7时,原式=6×(-7)=-42.