BC=ABsin22.5°=150×√(2-√2)/2=75√(2-√2) (cm)AC=ABcos22.5°=150×√(2+√2)/2=75√(2+√2) (cm)
AC =ABcos22.5°=100cos22.5°=92.39cmBC =ABsin22.5°=100sin22.5°=38.27cm
